document.write( "Question 1041607: if x + y = 12 and x - y = 1/3, then x^2 -y^2 = \n" ); document.write( "
Algebra.Com's Answer #656530 by jim_thompson5910(35256)\"\" \"About 
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x+y = 12
\n" ); document.write( "x-y = 1/3\r
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\n" ); document.write( "\n" ); document.write( "Multiply out the two equations (left sides group together, right sides group together)\r
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\n" ); document.write( "\n" ); document.write( "(x+y)*(x-y) = 12*(1/3)
\n" ); document.write( "(x+y)*(x-y) = 4
\n" ); document.write( "x^2 - y^2 = 4 ... difference of squares rule\r
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\n" ); document.write( "\n" ); document.write( "The final answer is 4.
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