document.write( "Question 1041607: if x + y = 12 and x - y = 1/3, then x^2 -y^2 = \n" ); document.write( "
Algebra.Com's Answer #656530 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! x+y = 12 \n" ); document.write( "x-y = 1/3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Multiply out the two equations (left sides group together, right sides group together)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x+y)*(x-y) = 12*(1/3) \n" ); document.write( "(x+y)*(x-y) = 4 \n" ); document.write( "x^2 - y^2 = 4 ... difference of squares rule\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The final answer is 4. \n" ); document.write( " |