document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1041506>Question 1041506</A>: <I><SPAN STYLE=\"word-break: break-all;\"> R.A Moyer of lowa State College found, in comprehensive tests carried out on 41 wet pavements, that the braking distance d (in feet) for a particular automobile traveling at v miles per hour was given approximated by d = o.0212*v^7/3<BR>\n" );
document.write( "1. approximate the braking distance to the nearest foot for the car traveling on wet pavement at 70 miles per hour.<BR>\n" );
document.write( "2. approximately how many feet would it take the car to stop on wet pavement if it were traveling at 50 miles per hour? ( Compute answer to the nearest foot.)  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #656512 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=656512\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> d = 0.0212*v^7/3<BR>\n" );
document.write( "at 70 mph, or v=70<BR>\n" );
document.write( "d=0.0212*4900*70^(1/3).  Or just do it on a calculator and raise 70 to the (7/3) power.<BR>\n" );
document.write( "d-428 feet.<BR>\n" );
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document.write( "d=0.0212*50^(7/3)<BR>\n" );
document.write( "d=195 feet.<BR>\n" );
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