document.write( "Question 1041472: robert has 50 coins, all in nickels and dimes, amounting to $3.50. how many nickels does he have?
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Algebra.Com's Answer #656438 by ikleyn(52790)\"\" \"About 
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\n" ); document.write( "robert has 50 coins, all in nickels and dimes, amounting to $3.50. how many nickels does he have?
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\n" ); document.write( "\n" ); document.write( "Similar problems were solved so many times, that I'd like to offer you a non-traditional solution.\r
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document.write( "Let us suppose for a moment that all  50  coins are  dimes. \r\n" );
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document.write( "Then their value is  50*10 = 500 cents = $5.  It is more than  $3.50 exactly in   $1.50 = 150 cents. \r\n" );
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document.write( "It is clear that the difference is due to presence of  5-cent nickels that we intently counted as 10-cent dimes.\r\n" );
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document.write( "It is also clear that the number of these  5-cent coins is  \"150%2F%2810-5%29\" = \"150%2F5\" = 30  to compensate the difference. \r\n" );
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document.write( "So, the answer is:  there are  30  of  5-cent nickels and  50-30 = 20  of  10-cent dimes.\r\n" );
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document.write( "Answer. There are 30 nickels and 20 dimes.\r\n" );
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\n" ); document.write( "\n" ); document.write( "For more traditional solutions see the lessons\r
\n" ); document.write( "\n" ); document.write( "    - Coin problems\r
\n" ); document.write( "\n" ); document.write( "    - More Coin problems\r
\n" ); document.write( "\n" ); document.write( "    - Kevin and Randy Muise have a jar containing coins\r
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