document.write( "Question 1041457: You have 23 coins totaling $2.75, how many quarters, nickles, and dimes do you have? \n" ); document.write( "
Algebra.Com's Answer #656437 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "You have 23 coins totaling $2.75, how many quarters, nickles, and dimes do you have?
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Let number of quarters, dimes, and nickels be Q, D, and N, respectively
\n" ); document.write( "Then we get: Q + D + N = 23 -------- eq (i)
\n" ); document.write( "Also, .25Q + .1D + .05N = 2.75 ----- eq (ii)
\n" ); document.write( "Since there are a lot of coins worth only $2.75, there MUST be a small number of quarters. Therefore, we start with 1 quarter, but 1, 2, and 3
\n" ); document.write( "quarters DO NOT result in meaningful numbers of nickels, or dimes. However, 4 quarters do.
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\n" ); document.write( "Let number of quarters be 4
\n" ); document.write( "Then we get: 4 + D + N = 23____D + N = 19 -------- eq (iii)
\n" ); document.write( ".25(4) + .1D + .05N = 2.75_____1 + .1D + .05N = 2.75____.1D + .05N = 1.75 ------- eq (iv)
\n" ); document.write( "- .1D - .1N = - 1.9 ----- Multiplying eq (iii) by - .1 ------- eq (v)
\n" ); document.write( "- .05N = - .15 ---------- Adding eqs (v) & (iv)
\n" ); document.write( "N, or number of nickels = \"%28-+.15%29%2F%28-+.05%29\", or 3\r
\n" ); document.write( "\n" ); document.write( "4 + D + 3 = 23 -------- Substituting 4 for Q and 3 for N in eq (i)
\n" ); document.write( "D + 7 = 23
\n" ); document.write( "D, or number of dimes = 23 – 7, or 16\r
\n" ); document.write( "\n" ); document.write( "This gives us: \"highlight_green%28matrix%283%2C2%2C+4%2C+quarters%2C+16%2C+dimes%2C+3%2C+nickels%29%29\" \n" ); document.write( "
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