document.write( "Question 90439This question is from textbook Beginning Algebra
\n" ); document.write( ": Please check to see if I got this correct: \r
\n" ); document.write( "\n" ); document.write( "Write the equation of the line passing through each of the given pairs of points. Write your result in slope-intercept form, where possible. \r
\n" ); document.write( "\n" ); document.write( "20. (-1,3) and (4,-2)\r
\n" ); document.write( "\n" ); document.write( "I got y= -5/3 x -2\r
\n" ); document.write( "\n" ); document.write( "Am I close or way off?
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Algebra.Com's Answer #65642 by malakumar_kos@yahoo.com(315)\"\" \"About 
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\n" ); document.write( " Write the equation of the line passing through each of the given pairs of points. Write your result in slope-intercept form, where possible.
\n" ); document.write( "20. (-1,3) and (4,-2)\r
\n" ); document.write( "\n" ); document.write( " x1,y1 = -1,3 and x2,y2 = 4,-2\r
\n" ); document.write( "\n" ); document.write( " eq'n is given by the formula y2-y1/y-y1 = x2-x1/x-x1
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\n" ); document.write( " -2-3/y-3 = 4-(-1)/x-(-1)\r
\n" ); document.write( "\n" ); document.write( " -5/y-3 = 5/x+1
\n" ); document.write( " -5(x+1) = 5(y-3)\r
\n" ); document.write( "\n" ); document.write( " -1(x+1) = y-3\r
\n" ); document.write( "\n" ); document.write( " -x-1 -y+3 = 0\r
\n" ); document.write( "\n" ); document.write( " -x-y+2 = 0
\n" ); document.write( " -y = x-2
\n" ); document.write( " y = -x+2 is the required eq'n in the slope intercept form
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