document.write( "Question 1041377: Show that, if x is real, the values of the expression \"%28x%5E2-3x%2B1%29%2F%282x%5E2-3x%2B2%29\" can only lie between -1 and 5/7. \n" ); document.write( "
Algebra.Com's Answer #656393 by robertb(5830)\"\" \"About 
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The domain of the expression is the set of all real numbers. (The discriminant \"b%5E2-4ac+=+-17\" of the denominator implies that it itself is never zero.)\r
\n" ); document.write( "\n" ); document.write( "Let \"y+=+%28x%5E2-3x%2B1%29%2F%282x%5E2-3x%2B2%29\".\r
\n" ); document.write( "\n" ); document.write( "==> \"y%282x%5E2-3x%2B2%29+=+x%5E2-3x%2B1\" (after multiplication; note that the denominator is never zero)\r
\n" ); document.write( "\n" ); document.write( "==> \"2yx%5E2-3yx%2B2y+=+x%5E2-3x%2B1\" <==> \"%282y-1%29x%5E2%2B%283-3y%29x%2B%282y-1%29+=+0\".\r
\n" ); document.write( "\n" ); document.write( "For x to have real values, the discriminant of this equation (with x as variable) must be greater than or equal to 0. \r
\n" ); document.write( "\n" ); document.write( "==> \"%283-3y%29%5E2-4%282y-1%29%5E2+%3E=+0\" <==> \"-7y%5E2-2y%2B5+%3E=0\", or\r
\n" ); document.write( "\n" ); document.write( "\"7y%5E2%2B2y-5+%3C=0\",\r
\n" ); document.write( "\n" ); document.write( "<==> \"%287y-5%29%28y%2B1%29+%3C=+0\"\r
\n" ); document.write( "\n" ); document.write( "The inequality is only true when y ∈ [-1, 5/7].\r
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