document.write( "Question 90431: Solve the system by substitution.
\n" ); document.write( " 3x – y = –7
\n" ); document.write( " x + y = –9
\n" ); document.write( " \n" ); document.write( "
Algebra.Com's Answer #65632 by malakumar_kos@yahoo.com(315)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( " Solve the system by substitution.
\n" ); document.write( "3x – y = –7
\n" ); document.write( "x + y = –9\r
\n" ); document.write( "\n" ); document.write( " 3x-y = -7.........(1)\r
\n" ); document.write( "\n" ); document.write( " x+y = -9..........(2)\r
\n" ); document.write( "\n" ); document.write( " From eq'n (2) we get x = -9-y
\n" ); document.write( " substituing for x in eq'n (1) we get 3(-9-y)+y = -7
\n" ); document.write( " -27-3y+y = -7\r
\n" ); document.write( "\n" ); document.write( " -2y = -7+27
\n" ); document.write( " y = 20/-2 = -10\r
\n" ); document.write( "\n" ); document.write( " substituting the value of y in eq'n (2),we get x-10 = -9
\n" ); document.write( " x = 10-9 = 1\r
\n" ); document.write( "\n" ); document.write( " The values of x = 1 and y = -10 are the required solution for the given eq'n \n" ); document.write( "
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