document.write( "Question 1041335: A bucket can be filled in 3 min. by the hot water tap, and 70 sec. by the cold water tap. Determine time taken to fill the bucket if both taps run with the same pressure as when they are open singly. \r
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document.write( "3 min. = 180 sec. \r
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document.write( "Let x = time. \r
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document.write( "How do I proceed?\r
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document.write( "Non-homework question. \n" );
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Algebra.Com's Answer #656298 by josmiceli(19441) You can put this solution on YOUR website! Rate of filling with hot water tap: \n" ); document.write( "[ 1 bucket filled ] / [ 3 min ] \n" ); document.write( "Rate of filling with cold water tap: \n" ); document.write( "[ 1 bucket filled ] / [ 70/60 min ] \n" ); document.write( "--------------------------- \n" ); document.write( "Add the 2 rates of filling to get the rate \n" ); document.write( "with both taps open \n" ); document.write( "Rate with both taps open: \n" ); document.write( "[ 1 bucket filled ] / [ t min ] \n" ); document.write( "--------------------------- \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Multiply both sides by \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "--------------------- \n" ); document.write( "the bucket is filled in 50.4 sec \n" ); document.write( "with both taps open \n" ); document.write( "----------------- \n" ); document.write( "check: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "error due to rounding off \n" ); document.write( " |