document.write( "Question 1041334: To mow a grass field a team of mowers planned to cover 15 hectares a day. After 4 working days they increased the daily productivity by 33×1/3% , and finished the work 1 day earlier than it was planned.
\n" ); document.write( "A) What is the area of the grass field?
\n" ); document.write( "B) How many days did it take to mow the whole field?
\n" ); document.write( "C) How many days were scheduled initially for this job?
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Algebra.Com's Answer #656295 by josgarithmetic(39630)\"\" \"About 
You can put this solution on YOUR website!
RT=J rule for work rates. J is for quantity of jobs, here being 1.\r
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\n" ); document.write( "\n" ); document.write( "Original plan was \"15%2At=1\" to expect \"1%2F15\" days.
\n" ); document.write( "NO!
\n" ); document.write( "Change that to j, unknown number of hectares.\r
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\n" ); document.write( "\n" ); document.write( "\"15t=j\"
\n" ); document.write( "\"t=j%2F15\", time in days to do j hectares.\r
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\n" ); document.write( "\n" ); document.write( "\"15%2A4%2B%2815%2A%284%2F3%29%29%2Ax=j\", ONE unit for j was performed.
\n" ); document.write( "x was number of days at the higher rate.
\n" ); document.write( "\"4%2Bx=j%2F15-1\"-----time taken total was one day less than expected. Solve this for j, and substitute.\r
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\n" ); document.write( "\n" ); document.write( "I did not finish this, but said how you can.\r
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