document.write( "Question 1041317: What is the sum of the geometric series linked below?\r
\n" ); document.write( "\n" ); document.write( "https://s31.postimg.org/upv8rqf7v/gseries.png\r
\n" ); document.write( "\n" ); document.write( "A.) 198.4375
\n" ); document.write( "B.) 96.875
\n" ); document.write( "C.) 196.875
\n" ); document.write( "D.) 396.875
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Algebra.Com's Answer #656283 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
solution is 196.875
\n" ); document.write( "you can use the sum of a geometric series formula, or you can just find A1 to A6 and add them up.\r
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\n" ); document.write( "\n" ); document.write( "the formula for An is An = A1 * r^(n-1)
\n" ); document.write( "A1 = 100
\n" ); document.write( "r = 1/2\r
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\n" ); document.write( "\n" ); document.write( "you get:
\n" ); document.write( "A1 = 100 * (1/2)^0 = 100 * 1 = 100
\n" ); document.write( "A2 = 100 * (1/2)^1 = 50 * 1/2 = 50
\n" ); document.write( "A3 = 100 * (1/2)^2 = 100 * 1/4 = 25
\n" ); document.write( "A4 = 100 * (1/2)^3 = 100 * 1/8 = 12.5
\n" ); document.write( "A5 = 100 * (1/2)^4 = 100 * 1/16 = 6.25
\n" ); document.write( "A6 = 100 * (1/2)^5 = 100 * 1/32 = 3.125\r
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\n" ); document.write( "\n" ); document.write( "add them up and you get 196.875\r
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\n" ); document.write( "\n" ); document.write( "the sum of a geometric series formula is Sn = (A1 * (1 - r^n)) / (1-r)
\n" ); document.write( "A1 = 100
\n" ); document.write( "r = 1/2
\n" ); document.write( "n = 6\r
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\n" ); document.write( "\n" ); document.write( "formula becomes S6 = (100 * (1 - (1/2)^6) / (1-r)
\n" ); document.write( "simplify to get S6 = (100 * (1 - 1/64) / (1 - 1/2)
\n" ); document.write( "simplify further to get S6 = (100 * 63/64) / (1/2)
\n" ); document.write( "simplify further to get S6 = 100 * 63/64 * 2
\n" ); document.write( "simplify further to get S6 = 100 * 126/64
\n" ); document.write( "simplify further to get S6 = 196.875\r
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\n" ); document.write( "\n" ); document.write( "you got the same answer two different ways.
\n" ); document.write( "it looks good.\r
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