The other tutor has made the error of assuming that the\r\n" );
document.write( "number with the equal digits must have both its digits\r\n" );
document.write( "as the same digit as the units digit of the desired number.\r\n" );
document.write( "This is not a requirement.\r\n" );
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document.write( "Let a = the tens digit\r\n" );
document.write( "Let b = the units digit\r\n" );
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document.write( "The number = 10a + b\r\n" );
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document.write( "Since the sum of the digits is 14,\r\n" );
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document.write( "a + b = 14, or b = 14 - a\r\n" );
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document.write( "Let c = the digit that is the same in the\r\n" );
document.write( "answer when 29 is subtracted from the number.\r\n" );
document.write( "So the answer when 29 is subtracted from the\r\n" );
document.write( "number is 10c + c or 11c \r\n" );
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document.write( "10a + b - 29 = 11c\r\n" );
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document.write( "So the system of equations is\r\n" );
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\r\n" );
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document.write( "This is underdetermined because there are more\r\n" );
document.write( "unknowns than equations.\r\n" );
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document.write( "We substitute 14 - a for b\r\n" );
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document.write( "10a + (14 - a) - 29 = 11c\r\n" );
document.write( "10a + 14 - a - 29 = 11c\r\n" );
document.write( "9a - 15 = 11c\r\n" );
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document.write( "9 is the smallest number in that equation in \r\n" );
document.write( "absolute value. So write 15 and 11 in terms \r\n" );
document.write( "of their nearest multiple of 9. So we write \r\n" );
document.write( "15 as 18 - 3 and 11 as 9 + 2\r\n" );
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document.write( "9a - (18 - 3) = (9 + 2)c\r\n" );
document.write( "9a - 18 + 3 = 9c + 2c\r\n" );
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document.write( "Divide through by 9\r\n" );
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document.write( "a - 2 + 3/9 = c + 2c/9\r\n" );
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document.write( "Get the fractions on one side, \r\n" );
document.write( "other terms on the other side:\r\n" );
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document.write( "2c/9 - 3/9 = a - 2 - c \r\n" );
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document.write( "The right side is an integer, so the left\r\n" );
document.write( "side is too. Let that integer be I.\r\n" );
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document.write( "2c/9 - 3/9 = I a - 2 - c = I; \r\n" );
document.write( " 2c - 3 = 9I\r\n" );
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document.write( "2 is the smallest number in that equation in \r\n" );
document.write( "absolute value. So write 3 and 9 in terms \r\n" );
document.write( "of their nearest multiple of 2. So we write \r\n" );
document.write( "3 as 2+1 and 9 as 8+1\r\n" );
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document.write( " 2c - 3 = 9I\r\n" );
document.write( " 2c - (2 + 1) = (8 + 1)I\r\n" );
document.write( " 2c - 2 - 1 = 8I + I\r\n" );
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document.write( "Divide through by 2\r\n" );
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document.write( " c - 1 - 1/2 = 4I + I/2\r\n" );
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document.write( "Get the fractions on one side, \r\n" );
document.write( "other terms on the other side:\r\n" );
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document.write( "c - 1 - 4I = I/2 + 1/2\r\n" );
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document.write( "The left side is an integer, so the\r\n" );
document.write( "right side is too. Let that integer be J.\r\n" );
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document.write( "c - 1 - 4I = J; I/2 + 1/2 = J\r\n" );
document.write( " I+1 = 2J\r\n" );
document.write( " I = 2J - 1\r\n" );
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document.write( "Substitute for I\r\n" );
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document.write( "c - 1 - 4(2J - 1) = J\r\n" );
document.write( " c - 1 - 8J + 4 = J\r\n" );
document.write( " c - 8J + 3 = J\r\n" );
document.write( " c = 9J - 3\r\n" );
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document.write( "The only value of J that will permit c to be\r\n" );
document.write( "a digit is J = 1\r\n" );
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document.write( "So c = 9J - 3 = 9(1) - 3 = 6\r\n" );
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document.write( "And since I = 2J - 1,\r\n" );
document.write( " I = 2(1) - 1, = 2 - 1 = 1\r\n" );
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document.write( "Now the system of equations becomes:\r\n" );
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document.write( "Since a - 2 - c = I\r\n" );
document.write( " a - 2 - 6 = 1\r\n" );
document.write( " a - 8 = 1\r\n" );
document.write( " a = 9\r\n" );
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document.write( "Since b = 14 - a\r\n" );
document.write( " b = 14 - 9 = 5\r\n" );
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document.write( "So the number is 95\r\n" );
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document.write( "Checking:\r\n" );
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document.write( " 95\r\n" );
document.write( " -29\r\n" );
document.write( " 66\r\n" );
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document.write( "Edwin
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document.write( "