document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1041272>Question 1041272</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a city it rain 328 days on an average in one year. what is the probability of not getting rain on<BR>\n" );
document.write( "1) two consecutive days.<BR>\n" );
document.write( "2) three consecutive days. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #656229 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=656229\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Cannot determine without additional info or making assumptions; the probability of rain on any given date is usually not a constant.\r<BR>\n" );
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document.write( "If you assume that there is a 328/365 chance of rain on any given day, then there is a 27/365 chance of no rain on any given day. Then the probability of no rain on two or three consecutive days is (27/365)^2 and (27/365)^3 respectively. </SPAN>\n" );
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