document.write( "Question 90376: A boat can go 22km downstream in 2 hours. The return trip takes 6 hours. What would be the speed of the boat if there were no current? What is the rate of the current? \n" ); document.write( "
Algebra.Com's Answer #65621 by ankor@dixie-net.com(22740)\"\" \"About 
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A boat can go 22km downstream in 2 hours. The return trip takes 6 hours. What would be the speed of the boat if there were no current? What is the rate of the current?
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\n" ); document.write( "Let x = speed of the boat in still water
\n" ); document.write( "Let y = speed of the current
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\n" ); document.write( "Speed up-stream = (x-y)
\n" ); document.write( "Speed down-stream = (x+y)
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\n" ); document.write( "Write two distance equations: Dist = time * speed
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\n" ); document.write( "2(x + y) = 22
\n" ); document.write( "6(x - y) = 22
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\n" ); document.write( "2x + 2y = 22
\n" ); document.write( "6x - 6y = 22
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\n" ); document.write( "Multiply the 1st equation by 3 and add to the 2nd equation:
\n" ); document.write( "6x + 6y = 66
\n" ); document.write( "6x - 6y = 22
\n" ); document.write( "-------------- adding eliminates y
\n" ); document.write( "12x = 88
\n" ); document.write( "x = 88/12
\n" ); document.write( "x = 7\"1%2F3\" mph boat speed in still water
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\n" ); document.write( "Find y using 6x - 6y = 22
\n" ); document.write( "6(7\"1%2F3\")- 6y = 22
\n" ); document.write( "44 - 6y = 22
\n" ); document.write( "-6y = 22 - 44
\n" ); document.write( "y = -22/-6
\n" ); document.write( "y = +3\"2%2F3\" mph is the current
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\n" ); document.write( "Check solutions using 2(x + y) = 22
\n" ); document.write( "2(7\"1%2F3\" + 3\"2%2F3\") = 22
\n" ); document.write( "2(11) = 22
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\n" ); document.write( "Did this make sense to you? Any questions?
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