document.write( "Question 1041236: Find S24 for the sequence 2,14,...12n-10\r
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Algebra.Com's Answer #656206 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\"2\" is the first term given in the sequence
\n" ); document.write( "1st term = a1 = 2\r
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\n" ); document.write( "\n" ); document.write( "The nth term is 12n-10
\n" ); document.write( "Plug in n = 24 to find the 24th term
\n" ); document.write( "24th term = a24 = 12*24-10 = 278\r
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\n" ); document.write( "\n" ); document.write( "Now we use the arithmetic sum formula
\n" ); document.write( "Sn = n*(a1+an)/2
\n" ); document.write( "S24 = 24*(a1+a24)/2
\n" ); document.write( "S24 = 24*(2+278)/2
\n" ); document.write( "S24 = 24*(280)/2
\n" ); document.write( "S24 = 24*140
\n" ); document.write( "S24 = 3360\r
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\n" ); document.write( "\n" ); document.write( "The sum of the first 24 terms of the sequence 2,124, ..., 12n-10 is 3360
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