document.write( "Question 1041228: Find the vertex,focus,directrix,and axis of symmetry in the given equation\r
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document.write( "(x+3)^2= -24y+60 \n" );
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Algebra.Com's Answer #656198 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! (x+3)^2= -24y+60 \n" ); document.write( "(x-h)^2=4p(y-k) \n" ); document.write( "-24y+60=-24(y-2.5) \n" ); document.write( "(x+3)^2=4*(-6)(y-2.5) \n" ); document.write( "focus is (h,k+p) or (-3,-2.5-6) or (-3,-8.5) \n" ); document.write( "directrix is y=(k-p)=2.5-(-6)=8.5 \n" ); document.write( "can rewrite as -24y=(x+3)^2-60 \n" ); document.write( "divide both sides by -24 and y=(-1/24)(x+3)^2+2.5. The vertex is (-3,2.5) \n" ); document.write( "The axis of symmetry is at x= -3 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |