document.write( "Question 1041178: Given the equation X = 1/x^2 - 1/y,
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Algebra.Com's Answer #656169 by Alan3354(69443)\"\" \"About 
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Given the equation X = 1/x^2 - 1/y,
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\n" ); document.write( "X = 1/x^2 - 1/y
\n" ); document.write( "Solve for y
\n" ); document.write( "x + 1/y = 1/x^2
\n" ); document.write( "1/y = 1/x^2 - x = 1/x^2 - x^3/x^2 = (1-x^3)/x^2
\n" ); document.write( "Invert
\n" ); document.write( "y = x^2/(1-x^3)
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\n" ); document.write( "@ x = 1 3/4 = 7/4, y = (49/16)/(1 - 343/64)
\n" ); document.write( "y = (49/16)/(-279/64) = -196/279
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\n" ); document.write( "Do the 2nd one the same way.
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