document.write( "Question 1041178: Given the equation X = 1/x^2 - 1/y,
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document.write( "find y when X = 1 3/4, x=1/2 \n" );
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Algebra.Com's Answer #656169 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Given the equation X = 1/x^2 - 1/y, \n" ); document.write( "find y when X = 1 3/4, x=1/2 \n" ); document.write( "-------- \n" ); document.write( "X = 1/x^2 - 1/y \n" ); document.write( "Solve for y \n" ); document.write( "x + 1/y = 1/x^2 \n" ); document.write( "1/y = 1/x^2 - x = 1/x^2 - x^3/x^2 = (1-x^3)/x^2 \n" ); document.write( "Invert \n" ); document.write( "y = x^2/(1-x^3) \n" ); document.write( "------- \n" ); document.write( "@ x = 1 3/4 = 7/4, y = (49/16)/(1 - 343/64) \n" ); document.write( "y = (49/16)/(-279/64) = -196/279 \n" ); document.write( "=================== \n" ); document.write( "Do the 2nd one the same way. \n" ); document.write( " \n" ); document.write( " |