document.write( "Question 1041179: Solve 12root3 + 2root3x = 4root6 \n" ); document.write( "

Algebra.Com's Answer #656163 by ikleyn(52847) $\"\"$ $\"About$

You can put this solution on YOUR website!
\n" ); document.write( " \r\n" ); document.write( " \r\n" ); document.write( " \r\n" ); document.write( " \r\n" ); document.write( "\n" ); document.write( "

\r
\n" ); document.write( "\n" ); document.write( "

\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Plots y = $\"12%2Asqrt%283%29+%2B+2%2Asqrt%283x%29\"$ and y = $\"4%2Asqrt%286%29\"$ \r
\n" ); document.write( "\n" ); document.write( "

\r
\n" ); document.write( "\n" ); document.write( "Comment from student: I'm sorry, I submitted the question wrong. It's actually: Solve 12root3 + 2root3(x) = 4root6,
\n" ); document.write( "so the x is not under the root sign. Sorry again!\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "My response:\r
\n" ); document.write( "\n" ); document.write( "

\r\n" );
document.write( " = .\r\n" );
document.write( "\r\n" );
document.write( "Divide both sides by . You will get\r\n" );
document.write( "\r\n" );
document.write( "6 + x = .\r\n" );
document.write( "\r\n" );
document.write( "Hence, x = .\r\n" );
document.write( "\r\n" );
document.write( "Answer.  x = .\r\n" );
document.write( "

\r
\n" ); document.write( "\n" ); document.write( "Solved.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );