document.write( "Question 1041179: Solve 12root3 + 2root3x = 4root6 \n" ); document.write( "
Algebra.Com's Answer #656131 by josgarithmetic(39626)\"\" \"About 
You can put this solution on YOUR website!
\"12%2Asqrt%283%29%2B2sqrt%283x%29=4%2Asqrt%286%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"2sqrt%283x%29=4sqrt%286%29-12sqrt%283%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%283x%29=2sqrt%286%29-6sqrt%283%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"3x=4%2A6-24%2Asqrt%286%29sqrt%283%29%2B36%2A3\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=4%2A3-8%2Asqrt%2818%29%2B36\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=48-8sqrt%2818%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=48-8%2Asqrt%282%2A3%2A3%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28x=48-72%2Asqrt%282%29%29\", but this will be a negative number, so no solution.\r
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\n" ); document.write( "\n" ); document.write( "What you originally wrote for your expression was not stated the way you really had as given to you. One of the other tutors already gave a solution.
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