document.write( "Question 90410: If i have a rectangle with an area of 66 sq cm, and a length of 13 cm less than four times the width, how do i find its dimensions? \n" ); document.write( "
Algebra.Com's Answer #65613 by checkley75(3666)\"\" \"About 
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L*W=AREA
\n" ); document.write( "LENGTH=4W-13 & WIDTH=W. THEN
\n" ); document.write( "(4W-13)W=66
\n" ); document.write( "4W^2-13W-66=0
\n" ); document.write( "(4W+11)(W-6)=0
\n" ); document.write( "4W+11=0
\n" ); document.write( "4W=-11
\n" ); document.write( "W=-11/4 NOT AN ANSWER.
\n" ); document.write( "W-6=0
\n" ); document.write( "W=6 ANSWER FOR THE WIDTH.
\n" ); document.write( "L=4*6-12
\n" ); document.write( "L=24-13
\n" ); document.write( "L=11 ANSWER.
\n" ); document.write( "PROOF
\n" ); document.write( "6*11=66
\n" ); document.write( "66=66
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