document.write( "Question 90410: If i have a rectangle with an area of 66 sq cm, and a length of 13 cm less than four times the width, how do i find its dimensions? \n" ); document.write( "
Algebra.Com's Answer #65613 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! L*W=AREA \n" ); document.write( "LENGTH=4W-13 & WIDTH=W. THEN \n" ); document.write( "(4W-13)W=66 \n" ); document.write( "4W^2-13W-66=0 \n" ); document.write( "(4W+11)(W-6)=0 \n" ); document.write( "4W+11=0 \n" ); document.write( "4W=-11 \n" ); document.write( "W=-11/4 NOT AN ANSWER. \n" ); document.write( "W-6=0 \n" ); document.write( "W=6 ANSWER FOR THE WIDTH. \n" ); document.write( "L=4*6-12 \n" ); document.write( "L=24-13 \n" ); document.write( "L=11 ANSWER. \n" ); document.write( "PROOF \n" ); document.write( "6*11=66 \n" ); document.write( "66=66 \n" ); document.write( " \n" ); document.write( " |