document.write( "Question 1041158: Need help using Sigma Notion to represent this series,
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document.write( "2 + 5 + 8 + 11 + 14 + 17
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document.write( "Solutions in Sigma Notion: https://postimg.org/image/z9biwjgjr/
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document.write( "Ty \n" );
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Algebra.Com's Answer #656082 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The first term is 2. The common difference is 3. The common difference is the value you add to any term to get the next term\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "eg: 5+3 = 8 or 14+3 = 17\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the nth term of the arithmetic sequence is\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a(n) = a1+d(n-1) \n" ); document.write( "a(n) = 2+3(n-1) \n" ); document.write( "a(n) = 2+3n-3 \n" ); document.write( "a(n) = -1+3n\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now this formula only works if you start at n = 1. Sometimes books will start at n = 0. So we need to add on 3 to correct for this\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-1+3n+3 = -1+3+3n = 2+3n\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If we started at n = 0, and we had 6 terms of 2+3n added up (n = 0 through n = 5), then we would have this summation\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the final answer is choice D \n" ); document.write( " \n" ); document.write( " |