document.write( "Question 1041144: brother 3 yrs ago was 2/3 sisters age.in one year he will be 3/4 her age. find his and her age. \n" ); document.write( "
Algebra.Com's Answer #656069 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! brother 3 yrs ago was 2/3 sisters age.in one year he will be 3/4 her age. find his and her age. \n" ); document.write( "=========== \n" ); document.write( "b-3 = (2/3)(s-3) \n" ); document.write( "b+1 = (3/4))(s+1) \n" ); document.write( "--------------------- \n" ); document.write( "3b-9 = 2s-6 \n" ); document.write( "4b+4 = 3s+3 \n" ); document.write( "---------------------- \n" ); document.write( "3b - 2s = 3 \n" ); document.write( "4b - 3s = -1 \n" ); document.write( "----- \n" ); document.write( "12b - 8s = 12 \n" ); document.write( "12b - 9s = -3 \n" ); document.write( "----- \n" ); document.write( "Subtract and solve for \"s\":: \n" ); document.write( "s = 15 (sister's age now) \n" ); document.write( "Solve for \"b\":: \n" ); document.write( "3b - 2s = 3 \n" ); document.write( "3b - 30 = 3 \n" ); document.write( "b = 11 years (brother's age now) \n" ); document.write( "------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "----------- \n" ); document.write( " |