document.write( "Question 1041101: five years ago a man was seven times as as old as his son.five years hence, the father will be three times as old as his son. find their present age.
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Algebra.Com's Answer #656065 by jorel555(1290)\"\" \"About 
You can put this solution on YOUR website!
Let f=father, s=son. Then:
\n" ); document.write( "f-5=7(s-5)
\n" ); document.write( "f+5=3(s+5)\r
\n" ); document.write( "\n" ); document.write( "f+5=3s+15
\n" ); document.write( "f-5=7s-35
\n" ); document.write( "10=-4s+50
\n" ); document.write( "4s=40
\n" ); document.write( "s=10
\n" ); document.write( "The son is 10; the father is 40. ☺☺☺☺
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