document.write( "Question 1041079: The area of a rectangle is 32cm^2. The width of the rectangle is 4 cm more than 3 times the length.\r
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document.write( "What is the length of the rectangle is cm?\r
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document.write( "Thanks in advance for any help, would love any tips on translating the word problem into an equation. \n" );
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Algebra.Com's Answer #656012 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! length is smaller and call it L \n" ); document.write( "width is 4 more than 3 times length. That is 4+3L \n" ); document.write( "The area, product, is 32 cm^2 \n" ); document.write( "L(4+3L)=32 \n" ); document.write( "4L+3L^2=32 \n" ); document.write( "3L^2+4L-32=0, just by rewriting and setting equal to 0. \n" ); document.write( "(3L-8)(L+4)=0. This is guess and check factoring. I need a product of -32 and 8 and 4 are factors that might work. If not, check 16 and 2 \n" ); document.write( "L= -4, can't work \n" ); document.write( "3L=8;L=8/3 cm \n" ); document.write( "3(8/3)+4; and 4+8=12 cm \n" ); document.write( "The width is 12 cm \n" ); document.write( "The length is 8/3 cm ANSWER. \n" ); document.write( "Their product is 32 cm^2. \n" ); document.write( " |