document.write( "Question 1041078: A rectangle with an area of 500 feet has a length that is 30 feet longer than twice its width. How many feet is the length of the rectangle?\r
\n" );
document.write( "\n" );
document.write( "Having trouble figuring out these rectangle word problems, I'm terrible at coming up with the actual equation, any help is much appreciated. \n" );
document.write( "
Algebra.Com's Answer #656009 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! A=L*W \n" ); document.write( "L=2W+30, that is 30 more than 2W. \n" ); document.write( "A=(2W+30)*W=500 sq ft \n" ); document.write( "Now multiply this out \n" ); document.write( "2W^2+30W=500. Notice that this looks like a quadratic, except it doesn't equal 0. \n" ); document.write( "subtract 500 on both sides \n" ); document.write( "2W^2+30W-500=0 Now it does. \n" ); document.write( "divide by 2. You don't have to, but it makes it easier \n" ); document.write( "2(W^2+15W-250)=0 \n" ); document.write( "since 2 can't equal 0, \n" ); document.write( "W^2+15W-250=0 (same as dividing by 2 both sides) \n" ); document.write( "facto, noting that 25 and 15 can make 10 if one is subtracted from the other. \n" ); document.write( "(W+25)(W-10)=0, set each of them equal to 0 \n" ); document.write( "W=-25 feet, which makes no sense. \n" ); document.write( "W=10 feet \n" ); document.write( "The width is 10 feet \n" ); document.write( "the length is 2W+30=50 feet ANSWER. Be sure that instead of W, you answer the question, which is the length. \n" ); document.write( "The area is 500 sq ft \n" ); document.write( " |