document.write( "Question 1040985: Divide 282 into two parts such that the eighth part of the first and the fifth part of the second are in the ratio 4:3. \n" ); document.write( "
Algebra.Com's Answer #655985 by ankor@dixie-net.com(22740)\"\" \"About 
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Divide 282 into two parts such that the eighth part of the first and the fifth part of the second are in the ratio 4:3.
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\n" ); document.write( "Two parts a & b
\n" ); document.write( "a + b = 282
\n" ); document.write( "\"the eighth part of the first and the fifth part of the second are in the ratio 4:3.\"
\n" ); document.write( "Using the decimal equiv, 1/8 = .125 and 1/5 = .200
\n" ); document.write( "\"%28.125a%29%2F%28.2b%29\" = \"4%2F3\"
\n" ); document.write( "cross multiply
\n" ); document.write( "4(.2b) = 3(.125a)
\n" ); document.write( ".8b =.375a
\n" ); document.write( "b = \"%28.375a%29%2F.8\"
\n" ); document.write( "b = .46875a
\n" ); document.write( "then
\n" ); document.write( "a + .46875a = 282
\n" ); document.write( "1.46875a = 282
\n" ); document.write( "a = \"282%2F1.46875\"
\n" ); document.write( "a = 192
\n" ); document.write( "find b
\n" ); document.write( "b = 282-192
\n" ); document.write( "b = 90
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\n" ); document.write( "The two parts are 192 and 90
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\n" ); document.write( "See if this works
\n" ); document.write( ".125(192) = 24
\n" ); document.write( ".200(90) = 18
\n" ); document.write( "24/18 = 4/3
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