document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1040971>Question 1040971</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two trains depart towards from two stations which distance is 900 km <BR>\n" );
document.write( "                     and meet in the middle of the distance. The departure of the first train is 1 hour<BR>\n" );
document.write( "                     later than the departure of the second train but it’s speed is 5 km/hour greater. <BR>\n" );
document.write( "                     Find the speed of each of trains.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #655949 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=655949\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The distance is 900km; they meet in the middle, having traveled 450km each. Let n be the speed of the first train. Then:<BR>\n" );
document.write( "(450/n)-1=450/(n+5)<BR>\n" );
document.write( "450(n+5)-(n²+5n)=450n<BR>\n" );
document.write( "450n+2250-n²-5n=450n<BR>\n" );
document.write( "n²+5n-2250=0<BR>\n" );
document.write( "(n+50)(n-45)=0<BR>\n" );
document.write( "n=45<BR>\n" );
document.write( "The first train went 45 kph for 10 hours; the second train went 50 kph for 9 hours &#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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