document.write( "Question 1041000: Solve for the exact solutions in the interval [0,2π)
\n" ); document.write( "cos(2x)=cos(x)\r
\n" ); document.write( "\n" ); document.write( "I got 0 but apparently there are more solutions
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #655922 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
cos(2x)=cos(x)
\n" ); document.write( "-----
\n" ); document.write( "2cos^2(x) - 1 = cos(x)
\n" ); document.write( "2cos^2(x) - cos(x) - 1 = 0
\n" ); document.write( "(2cos + 1)*(cos - 1) = 0
\n" ); document.write( "cos = 1
\n" ); document.write( "x = 0
\n" ); document.write( "-----
\n" ); document.write( "cos = -1/2
\n" ); document.write( "x = 2pi/3
\n" ); document.write( "x = 4pi/3
\n" ); document.write( "
\n" ); document.write( "
\n" );