document.write( "Question 1040955: Debbie runs 10km in 1 hour and 40 minutes. in the first half of the journey she runs at 5km/hr. how fast does she travel in the second half of the journey?\r
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Algebra.Com's Answer #655891 by ikleyn(52813)\"\" \"About 
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\n" ); document.write( "Debbie runs 10 km in 1 hour and 40 minutes. in the first half of the journey she runs at 5 km/hr.
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document.write( "First half of the distance is 5 km.\r\n" );
document.write( "Second half of the distance is 5 km, too.\r\n" );
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document.write( "For the first half of the distance she spent \"5%2F5\" = 1 hour.\r\n" );
document.write( "Hence, for the second part of the distance she spent 1 hour 40 minutes - 1 hour = 40 minutes.\r\n" );
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document.write( "Thus at the second part Debbie covered  5 km in 40 minutes = \"2%2F3\" hour.\r\n" );
document.write( "Then she traveled the second half at the speed of \"5%2F%28%282%2F3%29%29\" = \"%285%2A3%29%2F2\" = 7.5 \"km%2Fh\".\r\n" );
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document.write( "Answer.  7.5 \"km%2Fh\".\r\n" );
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First what you need to do to solve the problem is to read its condition attentively.\r
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