document.write( "Question 1040895: Find all values of $p$ such that$$2(x+4)(x-2p)$$has a minimum value of $-18$ over all real values of $x$. (In other words, we cannot have $x$ be nonreal.) \n" ); document.write( "
Algebra.Com's Answer #655875 by robertb(5830)\"\" \"About 
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The x-value that will give the minimum value will just be the average of the two roots, namely -4 and 2p. Their average is \"%28-4%2B2p%29%2F2+=+p-2\".\r
\n" ); document.write( "\n" ); document.write( "===> \"2%28p-2%2B4%29%28p-2-2p%29+=+-18\", \r
\n" ); document.write( "\n" ); document.write( "after direct substitution into the equation.\r
\n" ); document.write( "\n" ); document.write( "<===> (p+2)(-p-2) = -9 <===> \"%28p%2B2%29%5E2+=+9\" ===> p+2 = 3, or p+2 = -3\r
\n" ); document.write( "\n" ); document.write( "==> p = 1, or p = -5.
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