document.write( "Question 1040932: Help please \r
\n" ); document.write( "\n" ); document.write( "If an object is propelled upward from a height of s feet at an initial velocity of v feet per​ second, then its height h after t seconds is given by the equation h=-16t^2+vt+s, where h is in feet. If the object is propelled from a height of 8 feet with an initial velocity of 64 feet per​ second, its height h is given by the equation h=-16t^2+64t+8\r
\n" ); document.write( "\n" ); document.write( "After how many seconds is the height 36 ​feet?
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Algebra.Com's Answer #655869 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
h=-16t^2+64t+8
\n" ); document.write( "After how many seconds is the height 36 ​feet?
\n" ); document.write( "Solve:: -16t^2 + 64t+8 = 36
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\n" ); document.write( "-16t^2 + 64t - 26 = 0
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\n" ); document.write( "-8t^2 + 32t - 13 = 0
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\n" ); document.write( "t = 0.4589 sec
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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