document.write( "Question 1040904: Given sinA = 5/13 and cosB = 4/5, then to the nearest hundredth, sin(B-A)=\r
\n" ); document.write( "\n" ); document.write( "The only one's I know of are sin(A+B) and sin(A-B) so I don't know how to approach this question. Given the way the other two are set up I would guess that it would be sin(B-A)= sinB cosA - cosB sinA but I'm not totally sure
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Algebra.Com's Answer #655822 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
How about this?
\n" ); document.write( "\"sin%28x-y%29=sin%28x%29cos%28y%29-cos%28x%29sin%28y%29\"
\n" ); document.write( "So in this case \"x=B\" and \"y=A\".
\n" ); document.write( "So,
\n" ); document.write( "\"sin%28y%29=5%2F13\"
\n" ); document.write( " and
\n" ); document.write( "\"cos%28y%29=12%2F13\" or \"cos%28y%29=-12%2F13\"
\n" ); document.write( "and
\n" ); document.write( "\"cos%28x%29=4%2F5\"
\n" ); document.write( "and
\n" ); document.write( "\"sin%28x%29=3%2F5\" or \"sin%28x%29=-3%2F5\"
\n" ); document.write( "Take it from there and complete it.
\n" ); document.write( "Don't get hung up on the variables, they're just placeholders.
\n" ); document.write( "When you run into something like this where it's confusing, just change the variable names and keep your head straight.
\n" ); document.write( "Good luck!
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