document.write( "Question 1040904: Given sinA = 5/13 and cosB = 4/5, then to the nearest hundredth, sin(B-A)=\r
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document.write( "The only one's I know of are sin(A+B) and sin(A-B) so I don't know how to approach this question. Given the way the other two are set up I would guess that it would be sin(B-A)= sinB cosA - cosB sinA but I'm not totally sure \n" );
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Algebra.Com's Answer #655822 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! How about this? \n" ); document.write( " \n" ); document.write( "So in this case \n" ); document.write( "So, \n" ); document.write( " \n" ); document.write( " and \n" ); document.write( " \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( "Take it from there and complete it. \n" ); document.write( "Don't get hung up on the variables, they're just placeholders. \n" ); document.write( "When you run into something like this where it's confusing, just change the variable names and keep your head straight. \n" ); document.write( "Good luck! \n" ); document.write( " |