document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1040861>Question 1040861</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Andy wanted to go shopping, but didn't have very much money for what he wanted. He did, however, spend $17 on a shirt, 1/4 of the remaining amount on shoes, $741 on a jacket, $2000 on a horse, 1/4 of the remaining amount on a saddle, 4/5 of rest of his money on horse grain, and $150 for one month's board for the horse. He was left with nothing. How much money did he spend?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #655800 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=655800\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let n be the amount Andy had before he bought the horse grain. His last expense was 150. 150 represents 1/5 of what he had left. So, working backward:<BR>\n" );
document.write( "n/5=150<BR>\n" );
document.write( "n=750.<BR>\n" );
document.write( "Before that, he spent 1/4 of what he had left on a saddle, so 750 represents 3/4 of what he had, so<BR>\n" );
document.write( "3n/4=750<BR>\n" );
document.write( "n=750*4/3=1000<BR>\n" );
document.write( "Add 2741 for the horse and the jacket, and we're up to 3741--<BR>\n" );
document.write( "3n/4=3741<BR>\n" );
document.write( "n=4988<BR>\n" );
document.write( "Add 17 for the shirt, and we have $5005 as the total amount of money Andy spent!!!!!!\r<BR>\n" );
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