document.write( "Question 1040863: A geometric progression has a positive common ratio,and the sixth term is (5/4)^4,The sum of the first three terms and the sum of the third,fourth and fifth terms are in the ratio 16:25.Find the sum of the first three terms? \n" ); document.write( "
Algebra.Com's Answer #655781 by robertb(5830)\"\" \"About 
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Given:\r
\n" ); document.write( "\n" ); document.write( "1) \"a%5B6%5D+=+%285%2F4%29%5E4\", and \r
\n" ); document.write( "\n" ); document.write( "2) \"S%5B3%5D%2F%28a%5B3%5D%2Ba%5B4%5D%2Ba%5B5%5D%29+=+16%2F25\".\r
\n" ); document.write( "\n" ); document.write( "From #2, \r
\n" ); document.write( "\n" ); document.write( "==> \r
\n" ); document.write( "\n" ); document.write( "= \r
\n" ); document.write( "\n" ); document.write( "=\"1%2Fr%5E2+=+16%2F25\" ==> \"r%5E2=25%2F16\" ==> r= 5/4, since r > 0 as stipulated.\r
\n" ); document.write( "\n" ); document.write( "==> \"a%5B6%5D+=+a%5B1%5D%2Ar%5E5+=+%285%2F4%29%5E4\" \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "==> \"a%5B1%5D%2A%285%2F4%29%5E5+=+%285%2F4%29%5E4\" ==> \"a%5B1%5D+=+4%2F5\"\r
\n" ); document.write( "\n" ); document.write( "==>
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