document.write( "Question 1040833: I am confused on what to draw out as triangles, since there are no pictures. Thanks in advance!\r
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document.write( "Given the triangle ADC, segment BD is a perpendicular bisector of segment AC. Point B is the median of side AC. Why would triangle ABD be similar to triangle CBD?\r
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document.write( "*SAS
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Algebra.Com's Answer #655750 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "BD is congruent to BD by Reflexive Equality\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "AB is congruent to BC by definition of bisector.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Angle DBA is congruent to angle DBC by definition of perpendicular.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Triangle DBA congruent to triangle DBC by SAS\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " ![]() \n" ); document.write( " |