document.write( "Question 1040833: I am confused on what to draw out as triangles, since there are no pictures. Thanks in advance!\r
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\n" ); document.write( "\n" ); document.write( "Given the triangle ADC, segment BD is a perpendicular bisector of segment AC. Point B is the median of side AC. Why would triangle ABD be similar to triangle CBD?\r
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Algebra.Com's Answer #655750 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "BD is congruent to BD by Reflexive Equality\r
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\n" ); document.write( "\n" ); document.write( "AB is congruent to BC by definition of bisector.\r
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\n" ); document.write( "\n" ); document.write( "Angle DBA is congruent to angle DBC by definition of perpendicular.\r
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\n" ); document.write( "\n" ); document.write( "Triangle DBA congruent to triangle DBC by SAS\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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