document.write( "Question 1040821: Evaluate:\r
\n" ); document.write( "\n" ); document.write( " ∞
\n" ); document.write( " Σ (1/3)(-4/3)^k
\n" ); document.write( "k=1\r
\n" ); document.write( "\n" ); document.write( "I hope I asked this right, the infinite is on top of the sigma. K=1 is on the bottom. And the rest is to the right of the sigma. Thank you! Just want to check my answer, haven't done sequences since high school.
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Algebra.Com's Answer #655738 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "This is a geometric series of the form \"a%2Ar%5En\" where n is a whole number. \r
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\n" ); document.write( "\n" ); document.write( "In this case, \"a+=+1%2F3\" and \"r+=+-4%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "The rule is this: an infinite geometric series converges to a fixed number if and only if \"-1+%3C+r+%3C+1\"\r
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\n" ); document.write( "\n" ); document.write( "But because \"r+=+-4%2F3+=+-1.33\" (approx) is NOT in the interval \"-1+%3C+r+%3C+1\", this means that the infinite geometric series does NOT converge.\r
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\n" ); document.write( "\n" ); document.write( "So the geometric series diverges. It will not approach a fixed number>
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