document.write( "Question 90307: At what time after 5 o'clock will the hands of the clock be forming 120 degrees? \n" ); document.write( "
Algebra.Com's Answer #65573 by ankor@dixie-net.com(22740)\"\" \"About 
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At what time after 5 o'clock will the hands of the clock be forming 120 degrees?
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\n" ); document.write( "Let x = position of the minute hand when this occurs:
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\n" ); document.write( "Convert the hr hand to degrees.
\n" ); document.write( "360/12 = 30 degrees per hr
\n" ); document.write( "The portion of a 5 min interval of the hour hand would be:
\n" ); document.write( "x/60*30 = .5x
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\n" ); document.write( "Convert min hand do degrees
\n" ); document.write( "360/60 = 6 degrees per minute
\n" ); document.write( "Number of degrees by the minute hand would be 6x
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\n" ); document.write( "5 o'clock = 5 * 30 = 150 degrees (added to the hr hand degrees)
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\n" ); document.write( "Min hand position - hr hand position = 120 degrees
\n" ); document.write( "6x - (150 + .5x) = 120
\n" ); document.write( "6x - 150 - .5x = 120
\n" ); document.write( "6x - .5x = 120 + 150
\n" ); document.write( "5.5x = 270
\n" ); document.write( "x = 270-5.5
\n" ); document.write( "x = 49.1 min
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\n" ); document.write( "The time when the hands form a 120 degree angle would be 5:49.1
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