document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1040742>Question 1040742</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve for x:\r<BR>\n" );
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document.write( "x^2.5 = 15.758 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #655650 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=655650\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^2.5=15.758<BR>\n" );
document.write( "2.5 log x=log 15.758<BR>\n" );
document.write( "log x=log 15.758/2.5<BR>\n" );
document.write( "log x=1.197/2.5.  Without rounding, then take 10 and raise it to the power of the quotient.  That removes the log and gets x.<BR>\n" );
document.write( "x=3.013 rounding at the end.<BR>\n" );
document.write( "3.013^2.5=15.75788.<BR>\n" );
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