document.write( "Question 1040716: you have a jar of quarters and dimes worth a total of $10.20. If you have 69 coins in the jar, how many of them are quarters and how many of them are dimes?
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Algebra.Com's Answer #655607 by Boreal(15235)\"\" \"About 
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x=quarters
\n" ); document.write( "y=dimes
\n" ); document.write( "x+y=69
\n" ); document.write( ".25x+.10y=10.20
\n" ); document.write( "x+y=69
\n" ); document.write( "25x+10y=1020
\n" ); document.write( "multiply the first by -25
\n" ); document.write( "-25x-25y=-1725
\n" ); document.write( "25x+10y=1020
\n" ); document.write( "-15y=-705
\n" ); document.write( "y=47 dimes or $4.70
\n" ); document.write( "x=22 quarters or $5.50
\n" ); document.write( "They add to $10.20
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