document.write( "Question 1040715: Passing through (4,-8) and perpendicular to the line whose equation is x-5y=3\r
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document.write( "Write an equation for this line in point slope form:\r
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document.write( "Also\r
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document.write( "Write and equation for this line in slope-intercent form:\r
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document.write( "Please help \n" );
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Algebra.Com's Answer #655606 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! The line x-5y=3 may be written as 5y=x-3 or y= (1/5)x-(3/5), slope -intercept form. The slope of the line perpendicular to this line is the negative reciprocal of the coefficient of x. That is the negative reciprocal of (1/5). To find that, flip the fraction and change the sign. It is therefore -5. \n" ); document.write( "point slope form of the line that goes through (4,-8) perpendicular to the line given has slope -5 \n" ); document.write( "y-(-8)=-5(x-4) \n" ); document.write( "y+8=5(x-4) That is point-slope form \n" ); document.write( "y=5x-20-8 \n" ); document.write( "y=5x-28 That is slope-intercept form. \n" ); document.write( "Graph doesn't show x and y the same interval for each. \n" ); document.write( " |