document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=90318>Question 90318</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Would you please use the synthetic division to determine whether the first polynomial is a factor of the second.  State yes or no and show work.\r<BR>\n" );
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document.write( "x+3 , 6x^3 + 29x^2 + 32x -3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #65556 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=65556\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> use the synthetic division to determine whether the first polynomial is a factor of the second.  State yes or no and show work.\r<BR>\n" );
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document.write( "x+3 , 6x^3 + 29x^2 + 32x -3<BR>\n" );
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document.write( "-3)....6....29....32....-3<BR>\n" );
document.write( ".........6....11...-1..|..0\r<BR>\n" );
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document.write( "============<BR>\n" );
document.write( "x+3 is a factor of 6x^3+29x^2+32x-3 because the Remainder is zero.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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