document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1040645>Question 1040645</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find three consecutive even integers such that twice the product of the first two is 16 more than the product of the last two. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #655542 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=655542\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x, x+2, x+4 are integers<BR>\n" );
document.write( "2x(x+2)-16=(x+2)(x+4).  Twice the product of the first minus 16 will be the product of the second.<BR>\n" );
document.write( "2x^2+4x=x^2+6x+8, expanding.<BR>\n" );
document.write( "x^2-2x-24=0, collecting terms<BR>\n" );
document.write( "(x-6)(x+4)=0<BR>\n" );
document.write( "x=6,-4 are possibilities<BR>\n" );
document.write( "6,8,10 and -4,-2,0<BR>\n" );
document.write( "2(6*8)=96<BR>\n" );
document.write( "8*10=80, and add 16 get 96.<BR>\n" );
document.write( "So 6,8,10 are the integers<BR>\n" );
document.write( "check -4,-2,0<BR>\n" );
document.write( "2(-4*-2)=16<BR>\n" );
document.write( "That is 16 more than the product of -2*0<BR>\n" );
document.write( "so -4,-2, and 0 are also possible. </SPAN>\n" );
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