document.write( "Question 90319: The problem says factor:\r
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document.write( "x^2-25\r
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document.write( "x^2-7x-12\r
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document.write( "I forgot how to factor these so maybe if you just explain it briefly I might remember,thank you. \n" );
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Algebra.Com's Answer #65554 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! Ah yes...factoring!! \n" ); document.write( "1) Factor: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "This suggests that the factors will be of the form: \n" ); document.write( " \n" ); document.write( "So, in this case, n = 5 so the factors are: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2) Factor: \n" ); document.write( " \n" ); document.write( "The factors will have the form: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The two numbers come to mind are 3 and 4 becuase: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Now all you have to do is to make sure the signs of the two numbers, n and m, will give the correct signs (negative, in this case) for the sum and the product. \n" ); document.write( "But, there is a problem! \n" ); document.write( "To get a product of -12, the 3 and the 4 must have opposite signs, right? \n" ); document.write( "But if the 3 and the 4 have opposite signs, then their sum can never be -7, can it? \n" ); document.write( "So, scrap the 3 and the 4. \n" ); document.write( "What other factors of 12 are there? \n" ); document.write( "-1*12 or 1*-12 \n" ); document.write( "-2*6 or 2*-6 \n" ); document.write( "Looking at these factors, there's no way you are going to get a sum -7 \n" ); document.write( "So, you have to say that: \n" ); document.write( " \n" ); document.write( "Now if your expression had been: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "But it isn't, so you can't!\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |