document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1040673>Question 1040673</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Billy-joe purchased a 60 gallon pool for his farm. At 1:00 pm one day Billy-joe placed a hose which filled the pool at a rate of 3 gal/hr. After 10 hours, the horses and cows started drinking the water at a rate of 1 gal/hr. Five hours after that, he noticed  the animals and placed a second hose in the pool which filled in at a rate of 2 gal/hr. At what time was the pool finally filled? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #655539 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=655539\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3*10=30 gallons after 10 hours<BR>\n" );
document.write( "minus 1 gal/hr for 5 hours=25 gallons.<BR>\n" );
document.write( "If the animals are still drinking, the pool is effectively filling at 1 gal/hr, 2-1, and it will take 35 more hours to fill.<BR>\n" );
document.write( "If the animals aren't drinking, the pool will fill at 2 gal/hour and it will be full in 35/2 hours or 17.5 hours. </SPAN>\n" );
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