document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1040598>Question 1040598</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the amount after 4 years if $800 is invested at 8% compounded: <BR>\n" );
document.write( "a) Annually <BR>\n" );
document.write( "Amount = $_________ <BR>\n" );
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document.write( "b) Semiannually <BR>\n" );
document.write( "Amount= $__________ <BR>\n" );
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document.write( "c) Quarterly <BR>\n" );
document.write( "Amount= $__________ <BR>\n" );
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document.write( "d) Monthly <BR>\n" );
document.write( "Amount= $___________  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #655451 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=655451\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a.  Po(1+0.08/1)^4.  The one is the number of compoundings a year, and 4 is the total number of compoundings in the interval.  It is $1088.39<BR>\n" );
document.write( "b. Po(1+0.08/2)^8. The interest rate is halved inside, but the total number of compoundings have doubled.  $1094.86.  It should be a little more than annually and less than quarterly.<BR>\n" );
document.write( "c. Po(1+(.08)/4)^16=$1098.23<BR>\n" );
document.write( "d. Po(1+(.08)/12))^48=$1100.53 </SPAN>\n" );
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