document.write( "Question 1040562: Find sin2x from the given information.\r
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Algebra.Com's Answer #655421 by ikleyn(52921)\"\" \"About 
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document.write( "Use this formula of Trigonometry\r\n" );
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document.write( "sin(2x) = 2*sin(x)*cos(x).\r\n" );
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document.write( "You just know that sin(x) = \"-3%2F5\" (it is given).\r\n" );
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document.write( "Based on it, you can calculate\r\n" );
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document.write( "cos(x) = -\"sqrt%281+-+sin%5E2%28x%29%29\" = -\"sqrt%281+-%28-3%2F5%29%5E2%29\" = -\"sqrt%281-9%2F25%29\" = -\"sqrt%28%2825-9%29%2F25%29\" = -\"sqrt%2816%2F25%29\" = -\"4%2F5\".\r\n" );
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document.write( "Notice that the sign before the square root is negative, since the function cosine is negative for x in Q3.\r\n" );
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document.write( "Now you are on the finish line to calculate sin(2x):\r\n" );
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document.write( "sin(2x) = 2*sin(x)*cos(x) = \"2%2A%28-3%2F5%29%2A%28-4%2F5%29\" = \"24%2F25\".\r\n" );
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document.write( "Answer.  sin(2x) = \"24%2F25\".\r\n" );
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