document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1040549>Question 1040549</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the side of a square equals the length of a rectangle. the width of the rectangle is 4 meters longer than its length. The sum of the areas of the square and the rectangle is 240 square centimeters. find the side of the square. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #655385 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=655385\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> side of square=s<BR>\n" );
document.write( "dimensions of rectangle are s and s+4<BR>\n" );
document.write( "Area of square is s^2<BR>\n" );
document.write( "Area of rectangle is s^2+4s, product of l*w<BR>\n" );
document.write( "They add to 240 cm^2<BR>\n" );
document.write( "Therefore, s^2+s^2+4s=240<BR>\n" );
document.write( "2s^2+4s-240=0<BR>\n" );
document.write( "2(s^2+2s-120)=0<BR>\n" );
document.write( "(s+12)(s-10)=0<BR>\n" );
document.write( "s=10,-12<BR>\n" );
document.write( "use positive root only<BR>\n" );
document.write( "square area is 10*10=100<BR>\n" );
document.write( "rectangle area is 10*14=140<BR>\n" );
document.write( "They add to 240 sq cm<BR>\n" );
document.write( "side is 10 cm </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );