document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1040548>Question 1040548</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1) A mother is five times as old as her daughter. If the sum of their ages 6 years ago was 60, find their present ages.<BR>\n" );
document.write( "2) A boy is 12 years old. His mother is 4 times as old. In x years time, the mother will be three times as old as the son. Form an equation in x and hence find x. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #655383 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=655383\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> m = 5d<BR>\n" );
document.write( "m-6+d-6 = 60 substitute for m:<BR>\n" );
document.write( "5d-6+d-6 = 60<BR>\n" );
document.write( "6d-12 = 60<BR>\n" );
document.write( "6d = 72<BR>\n" );
document.write( "d = 12 The daughter is 12 and the mother is 5(12) = 60<BR>\n" );
document.write( "-------------------------------------<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "(12-6)+(60-6) = 60 Correct. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );