document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1040542>Question 1040542</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help solving this problem please!\r<BR>\n" );
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document.write( "f(x) = sqrt(x+5) and g(x)=x-3\r<BR>\n" );
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document.write( "I need to find (f/g)(-1) and I'm coming up with:\r<BR>\n" );
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document.write( "sqrt((x+5)(x-3))/ x-3\r<BR>\n" );
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document.write( "I'm also asked to find the domain and come up with:\r<BR>\n" );
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document.write( "(&#8722;&#8734;,&#8722;5]&#8746;(3,&#8734;)\r<BR>\n" );
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document.write( "am I on the right track?\r<BR>\n" );
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document.write( "Thank you for any guidance! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #655378 by </B><A HREF=/tutors/aboutme.mpl?userid=Aldorozos><B>Aldorozos(172)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Aldorozos><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=655378\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First you have to divide both functions<BR>\n" );
document.write( "Sqrt(x+5)/x-3 now you have to replace x with  -1<BR>\n" );
document.write( "Sqrt(-1+5)/(-1-3)= sqrt4/-4 2/-4= -1/2\r<BR>\n" );
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document.write( "We know that sqrt can not be less than zero. In other words sqrt is always zero or greater than zero<BR>\n" );
document.write( "We also know that the denominator can't be zero<BR>\n" );
document.write( "Now we look at <BR>\n" );
document.write( "Sqrt(x+5) this has to be greater or equal to zero. This means that x has to be -5 or greater than -5\r<BR>\n" );
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document.write( "We said that the denominator can't be zero. This means that x-3 can't be zero the only time x-3 is zero is when x is 3. Therefore x can't be 3\r<BR>\n" );
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document.write( "We said x has to be -5 or greater and it can't be 3<BR>\n" );
document.write( "The way we can rewrite this statement is<BR>\n" );
document.write( "[-5,3) and (3,infinitie) <BR>\n" );
document.write( "I think the statement you have written is not accurate when you said<BR>\n" );
document.write( "(Infiniti,-5]. By saying that you are saying the numbers less than -5 are acceptable. You can try -6 for example and put it under the square root. You will get sqrt(-6+5)=sqrt of -1 we know that we don't have any real number that if multipiled by itself could give us -1. In other words we can't have a nevative number under sqrt. This means the number has to be -5 or greater than -5. Also that nber can't be 3.<BR>\n" );
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