document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1040504>Question 1040504</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Let f (x) = sqr symbol x + 6 and g(x) = x – 8\r<BR>\n" );
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document.write( "(a) Find (f/g) (-2) show work\r<BR>\n" );
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document.write( "(b) Find the domain of the quotient function f/g. Explain </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #655363 by </B><A HREF=/tutors/aboutme.mpl?userid=Aldorozos><B>Aldorozos(172)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Aldorozos><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=655363\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Divide both equation\r<BR>\n" );
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document.write( "Sqrt x+6/x-8<BR>\n" );
document.write( "Replace x with -2\r<BR>\n" );
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document.write( "4/-10 = -2/5= - .4\r<BR>\n" );
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document.write( "Domain: the denominator can't be zero<BR>\n" );
document.write( "Sqrt of a number can't be negative which means under the sqrt can't be negative\r<BR>\n" );
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document.write( "X-8=8 therefor x can't be eight since 8 can make the denominator as zero\r<BR>\n" );
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document.write( "Sqrt x+ 6 has to be greater than zero. X+6= 0 therefore x can be -6 or any number greater than 6 except 8 </SPAN>\n" );
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