document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1040517>Question 1040517</A>: <I><SPAN STYLE=\"word-break: break-all;\"> when a stone is dropped into a deep well, the number of seconds until the sound of a splash is heard is given by the formula<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=t=sqrt%28x%29%2F4%2Bx%2F1100 ALIGN=MIDDLE  ALT=\"t=sqrt%28x%29%2F4%2Bx%2F1100\"   DISABLED_style= \"max-width:90%; height:auto;\" > where x is the depth of the well feet. For one particular well, the splash is heard 14 seconds after the stone is released. <BR>\n" );
document.write( "1. How deep (to the nearest foot) is the well?<BR>\n" );
document.write( "2. For a different well, the sound of the splash is heard 2 seconds after the stone is release. How deep (to the nearest foot) is the well?<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #655332 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=655332\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve for x:<BR>\n" );
document.write( "sqrt(x)/4+x/1100 = 14<BR>\n" );
document.write( "(275*sqrt(x)+x)/1100 = 14<BR>\n" );
document.write( "275*sqrt(x)+x = 15400<BR>\n" );
document.write( "275*sqrt(x) = 15400-x<BR>\n" );
document.write( "75625x = (15400-x)^2<BR>\n" );
document.write( "75625x = x^2-30800x+237160000<BR>\n" );
document.write( "-x^2+106425x-237160000 = 0<BR>\n" );
document.write( "x^2-106425 x+237160000 = 0<BR>\n" );
document.write( "x^2-106425 x = -237160000<BR>\n" );
document.write( "x^2-106425 x+11326280625/4 = 10377640625/4<BR>\n" );
document.write( "(x-106425/2)^2 = 10377640625/4<BR>\n" );
document.write( "x-106425/2 = (1375*sqrt(5489))/2 or x-106425/2 = -(1375*sqrt(5489))/2<BR>\n" );
document.write( "x = 106425/2+(1375*sqrt(5489))/2 or x-106425/2 = -(1375*sqrt(5489))/2<BR>\n" );
document.write( "x = 106425/2+(1375*sqrt(5489))/2 or x = 106425/2-(1375*sqrt(5489))/2<BR>\n" );
document.write( "sqrt(x)/4+x/1100 => 1/4 sqrt(106425/2-(1375*sqrt(5489))/2)+(106425/2-(1375 sqrt(5489))/2)/1100  =  1/4*sqrt(106425/2-(1375*sqrt(5489))/2)+(106425/2-(1375*sqrt(5489))/2)/1100 ~~ 14<BR>\n" );
document.write( "So this solution is correct. You can do the other one and you will see it's incorrect. Therefore, the solution is:<BR>\n" );
document.write( "x = 106425/2-(1375*sqrt(5489))/2 You don't need me to finish it off, use  your calculator. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );